Answer:
Current = 3 Amperes
Explanation:
Given the following data;
Quantity of charge = 6 C
Time = 2 seconds
To find how many amps are moving through this wire;
Mathematically, the quantity of charge passing through a conductor is given by the formula;
Quantity of charge = current * time
Substituting into the formula, we have;
6 = current * 2
Current = 6/2
Current = 3 Amperes
. What is the mass of an object if it is pulled by a 5 Newton force and it accelerates at a rate of 20 m/s/s?
Please help ASAP
F = ma
so, we can write it as;
= 5 = m × 20
= 5/20 = m
= 1/4 = m
= 0.25 kg = m
[tex]what \: is \: light \: {?} [/tex]
Light is a form of electromagnetic radiation with a wavelength which can be detected by the human eye. It is a small part of the electromagnetic spectrum and radiation given off by stars like the sun. Animals can also see light. The study of light, known as optics, is an important research area in modern physics.
Answer:
Light is a form of energy which produces the sensation of sight .hope it is helpful to you
A 1.00kg object vibrates at the end of a vertical spring. If the frequency of the vibration is 1.25Hz, what is the spring constant?
Answer:
61.62 N/m
Explanation:
Applying,
1/F = 2π[tex]\sqrt{m/k}[/tex].................. Equation 1
Where F = frequency, m = mass of the spring, k = spring constant, π = pie.
make k the subject of the equation
k = m(2πF)²............... Equation 2
From the question,
Given: m = 1.00 kg, F = 1.25 Hz
Constant: π = 3.14
Substitute these values into equation 2
k = 1(2×3.14×1.25)²
k = 61.62 N/m
what happens to the piece of plastic?
Answer:
it reheated and use form another
help asap please!!!!
Answer:
true is correct answer answer
Block A of 5 kg with a speed of 3 m/s collides with block B of 10 kg that is stationary. After the collision, block B travels with a speed of 2 m/s
Answer:
-1m/s
Explanation:
We can calculate the speed of block A after collision
According to collision theory:
MaVa+MbVb = MaVa+MbVb (after collision)
Substitute the given values
5(3)+10(0) = 5Va+10(2)
15+0 = 5Va + 20
5Va = 15-20
5Va = -5
Va = -5/5
Va = -1m/s
Hence the velocity of ball A after collision is -1m/s
Note that the velocity of block B is zero before collision since it is stationary
Determine the mechanical advantage of a car jack that uses an input force of 30 N and provides an output force of 600 N. pls answer quick
Answer:
Mechanical Advantage of car jack is 20
why colour of sky appear blue ¯\_(ツ)_/¯
Explanation:
During the day the sky looks blue because it's the blue light that gets scattered the most. It's redirected into many different directions all over the sky, whereas the other wavelengths aren't scattered as much. Sunlight reaches Earth's atmosphere and is scattered in all directions by all the gases and particles in the air. Blue light is scattered more than the other colors because it travels as shorter, smaller waves. This is why we see a blue sky most of the time. White light is composed of seven light and among them, blue light scatters the most as the wavelength of the blue light is comparable to the size of particles in the atmosphere. So, the sky appears blue. Hence, the sky appears blue because the fine particles in the atmosphere scatter light of shorter wavelengths! :D
Which of the following is a part of a constitutional republic
Laws are written by a king
People must obey the president.
People vote for representatives.
People cannot affect the government.
4. A current of 3.00 A flows through a resistor when it is connected to a
12.0 - V battery. What is the resistance of the resistor?*
2.4 ohms
36 ohms
4 ohms
0.3 ohms
Answer:
V=IR
12 = 3 ×RESISTANCE
RESISTANCE=12/3
=4 Ohms
answer is the third option
- What will be the field strength from a 1.25* 10^-3 when measured 0.4m from the charge?
Answer:
Explanation:
I'm assuming your charge is in Coulombs so I will proceed that way. The formula for this electric field problem is
[tex]E=\frac{kQ}{r^2}[/tex] where k = 9.0 × 10⁹. Filling in:
[tex]E=\frac{(9.0*10^9)(1.25*10^{-3})}{.4^2}[/tex] gives us an electric field value of
7.0 × 10⁷ N/C
What is the force weight of a jaguar who jumps 3 meters to a tree branch with 2670 J of work?
Answer:
[tex]we \: know \: energy \: = \: force \: \times distance \\ e = f \times d \\ so \: f \: = \frac{e}{d} \\ so \: th \: force \: here \: = (\frac{2670}{3}) newton \\ = 890newton[/tex]
Hope it helps
PLEASE HELP!!! I have an electromagnet. If I detach the two wires from the battery and reattach them to the opposite terminals, how would that change the current and magnetic field?
Explanation:
hope it helps thanks
pls mark me as brainliest
help pls i really don't know the answers
Answer:
In the first one circle : luster
second circle: atsuete seeds
third: dentures
Explanation:
Well I ain’t sure
Explain how a truss bridge is so stable.
Answer:
Truss bridge, bridge with its load-bearing structures composed of a series of wooden or metal triangles, known as trusses. Given that a triangle cannot be distorted by stress, a truss gives a stable form capable of supporting considerable external loads over a large span.
Explanation:
Load-bearing capacity of truss bridges is huge due to the structure of interconnecting triangles. The structure effectively manages both compression and tension by spreading the load from the roadway throughout its intricate structure
How do an object's mass and the forces acting upon an object affect its motion?
Answer:
Acceleration. When an external force acts on an object, the change in the object's motion will be directly related to its mass. This change in motion, known as acceleration, depends upon the object's mass and the strength of the external force.
Look at the diagrams. Each model the arrangement of particles in a substance.
Which diagram is the best model for a solid?
Substance A
Substance B
Substance C
Answer:
a
Explanation:
because it has compact molecules
The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth of the liquid in the tank?
[tex] \orange{\underline{\huge{\bold{\textit{\green{\bf{QUESTION}}}}}}}[/tex]
The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth of the liquid in the tank?
[tex]{\bold{\blue{GIVEN}}}[/tex]
REFRACTIVE INDEX = 1.3
APPARENT DEPTH = 7.7 cm
[tex]{ \bold{\green{To \: Find}}}[/tex]
REAL DEPTH OF THE OBJECT.
[tex]{\red{FORMULA \: \: USED }}[/tex]
[tex]Reflective \: Index = \frac{Real \: Depth}{Apparent \: Depth } [/tex]
[tex] \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}[/tex]
Refractive Index = 1.3
Apparent Depth = 7.7 cm
Putting the values in the formula:-
[tex]Reflective \: Index = \frac{Real \: Depth}{Apparent \: Depth } \\ \\ 1.3 = \frac{Real \: Depth}{7.7 \: cm} \\ \\ 1.3 \times 7.7 = Real \: Depth \\ \\ 10.01 \: \: cm = Real \: Depth[/tex]
The energy stored by any pair of positive charges is inversely proportional to the distance between them, and directly proportional to their charges. Three identical point charges start at the vertices of an equilateral triangle, and this configuration stores 15 Joules of energy. How much more energy, in Joules, would be stored if one of these charges was moved to the midpoint of the opposite side
Answer:
U = 25 J
Explanation:
The energy in a set of charges is given by
U = [tex]k \sum \frac{q_i}{r_i}[/tex]
in this case we have three charges of equal magnitude
q = q₁ = q₂ = q₃
with the configuration of an equilateral triangle all distances are worth
d = a
U = k ( [tex]\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3}[/tex] )
we substitute
15 = k q² (3 / a)
k q² /a = 5
For the second configuration a load is moved to the measured point of the other two
d₁₃ = a
The distance to charge 2 that is at the midpoint of the other two is
d₁₂ = d₂₃ = a / 2
U = k (\frac{q_1q_2}{ r_1_2 } + \frac{q_1q_3}{r_1_3} + \frac{q_2q_3}{r_2_3})
U = k q² ( [tex]\frac{2}{a} + \frac{1}{a} + \frac{2}{a}[/tex] )
U = (kq² /a) 5
substituting
U = 5 5
U = 25 J
Explain why a smart meter monitors the amount of electrical energy being used as well as the time at which it is being used.
Answer:
Smart Meters measure both the amount of electrical energy used and the time at which it is being used because they are used to monitor the energy consumption at real time, such that the time of use of energy can be monitored, thereby enabling several utility functions for load sharing and maintenance, including;
i) Time of use tariffs, where energy is billed based on peak and off peak periods, which increases profits to the producer, reduces cost for some consumers, encourages more even hourly and daily usage of electricity, lower maintenance cost, lower capital expenditure for peak stations, and reduces carbon emission
ii) Guarantees more accurate energy consumption measurement and billing
iii) Accurate crew dispatch to fault locations
iv) Prevent fraud due to tampering with meter
v) Increase customer confidence in billing
Explanation:
Tenemos un Cable de cobre de 1 km de longitud cuya sección es de 2 milímetros al cuadrado y queremos saber la resistencia que señalara el ohmetro , su temperatura es de 20°
Answer:
8.5 Ω
Explanation:
La resistencia de un material es directamente proporcional a su longitud e inversamente proporcional al área de la sección transversal.
La fórmula de la resistencia (R) viene dada por:
R = ρL/A
Donde ρ es la resistividad del material, L es la longitud del material y A es el área de la sección transversal del material.
Dado que:
L = 1 km = 1000 m, A = 2 mm² = 2 * 10⁻⁶ m², ρ (cobre) = 1.7 * 10⁻⁸ Ωm
Sustituyendo da:
R = 1,7 * 10⁻⁸ * 1000/2 * 10⁻⁶
R = 8.5 Ω
Objects tend to "keep on doing what they're doing" (unless acted upon by an unbalanced force). When your car abruptly stops, the seat belt provides the
that brings you from a state of motion to a state of rest.
a. spring force
b.gravity force
c. unbalanced force
d.friction force
Answer:
unbalanced force
Explanation:
well the seat brings you to a state of rest duw to the unbalanced force of the car stopping and the seat belt keeping you in place
If each metal is hit with light at a minimum wavelength, can I vary the intensity of the light to start emitting electrons?
It is true that the metal will begin to emit electrons at varied speeds depending on the intensity of the light when it is struck at a minimal wavelength.
What is meant by wavelength?When a waveform signal is propagated in space or over a wire, the wavelength is the separation between two identical locations (adjacent crests) in the adjacent cycles.
If you are employing light with a high enough frequency, the number of electrons ejected grows as the light source's brightness rises.
The velocity of the expelled electrons increases as the frequency is raised above the threshold.
Thus, the metal will begin to emit electrons at varied speeds depending on the intensity of the light when it is struck at a minimal wavelength.
To learn more about Wavelength, refer to the below link:
https://brainly.com/question/1263539
# SPJ2
A car traveling at an initial velocity of 12.0 m/s accelerates at a constant rate to 20.0 m/s over a time of 4.00 s. How far did the car travel during this time (m)?
What the effect positively charged objects and negatively charged objects have on each other
Answer:
often Positive and negative charges balance each other which gives an overall neutral charge. if they are unbalanced then it will result in static electricity.
What is El Niño and La Niña? Where does this phenomena originate (land or water)?
Answer/Explanation:
El Niño and la Niña, is a very rare/complex phenomenon that occurs in water. El Niño and La Niña are climate patterns in the Pacific that can affect weather everywhere basically worldwide.
~ LadyBrain
A student does 686 J of work on an object in 3.1 seconds. What is the power output of the student?
Answer:
221.29 Watts
Explanation:
P=W/t
P=686/3.1
P=221.29 Watts
10. Inertia causes your books on the car seat to continue moving forward even after you brake. TrueFalse 11. Tires with little or no tread do not have good traction on a wet, snowy, or icy road. TrueFalse 12. When driving on ice and snow, traction is poorest when the temperature is near 32 degrees F. TrueFalse 13. The more energy of motion that a car has, the less time and distance it will take to stop. TrueFalse 14. To help slow a car using engine braking, just take your foot off the accelerator. TrueFalse
10. True
11. True
12. True
13. False
14. False
Hope this helps!!
An electric circuit consists of a variable resistor connected to a source of constant potential difference. If the resistance of the resistor is doubled, the current through the resistor is
Answer:
halved.
Explanation:
Given the following data;
Potential difference = constant
Resistance = 2 * resistance = 2R
To find the current I;
Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
[tex] V = IR[/tex]
Where;
V represents voltage measured in voltage.
I represents current measured in amperes.
R represents resistance measured in ohms.
Making current (I) the subject of formula, we have;
[tex] I = \frac {V}{R} [/tex]
Substituting into the formula, we have;
[tex] I = \frac {V}{2R} [/tex]
[tex] I = \frac {1}{2} * \frac {V}{R} [/tex]
[tex] I = \frac {1}{2} * I [/tex]
Therefore, if the resistance of the resistor is doubled, the current through the resistor is halved.
1. A 2.5 kg led projector is launched as a projectile off a tall building. At one point, as it
is flying through the air it has a velocity of 24 m/s and a height of 14 m.
a) Find the potential energy
b) Find the kinetic energy
c) Find the total mechanical energy
d) Find the potential energy at a height of 8.7 m
e) Find the kinetic energy at that same height. (Hint – the total energy is always the same
as in part c)
f) Find the velocity at that height
g) Find the velocity at a height of 11.6 m
h) At what height would the velocity be 26 m/s?
i) What is the velocity just before it smashes into the ground?
See
Answer:
Explanation:
I got everything but i. Don't know why but it's eluding me. So let's do everything but that.
a. PE = mgh so
PE = (2.5)(98)(14) and
PE = 340 J
b. [tex]KE=\frac{1}{2}mv^2[/tex] so
[tex]KE=\frac{1}{2}(2.5)(14)^2[/tex] and
KE = 250 J
c. TE = KE + PE so
TE = 340 + 250 and
TE = 590 J
d. PE at 8.7 m:
PE = (2.5)(9.8)(8.7) and
PE = 210 J
e. The KE at the same height:
TE = KE + PE and
590 = KE + 210 so
KE = 380 J
f. The velocity at that height:
[tex]380=\frac{1}{2}(2.5)v^2[/tex] and
[tex]v=\sqrt{\frac{2(380)}{2.5} }[/tex] so
v = 17 m/s
g. The velocity at a height of 11.6 m (these get a bit more involed as we move forward!). First we need to find the PE at that height and then use it in the TE equation to solve for KE, then use the value for KE in the KE equation to solve for velocity:
590 = KE + PE and
PE = (2.5)(9.8)(11.6) so
PE = 280 then
590 = KE + 280 so
KE = 310 then
[tex]310=\frac{1}{2}(2.5)v^2[/tex] and
[tex]v=\sqrt{\frac{2(310)}{2.5} }[/tex] so
v = 16 m/s
h. This one is a one-dimensional problem not using the TE. This one uses parabolic motion equations. We know that the initial velocity of this object was 0 since it started from the launcher. That allows us to find the time at which the object was at a velocity of 26 m/s. Let's do that first:
[tex]v=v_0+at[/tex] and
26 = 0 + 9.8t and
26 = 9.8t so the time at 26 m/s is
t = 2.7 seconds. Now we use that in the equation for displacement:
Δx = [tex]v_0t+\frac{1}{2}at^2[/tex] and filling in the time the object was at 26 m/s:
Δx = 0t + [tex]\frac{1}{2}(-9.8)2.7)^2[/tex] so
Δx = 36 m
i. ??? In order to find the velocity at which the object hits the ground we would need to know the initial height so we could find the time it takes to hit the ground, and then from there, sub all that in to find final velocity. In my estimations, we have 2 unknowns and I can't seem to see my way around that connundrum.